How do you integrate $int (5-e^x)/(e^(2x))dx$ ?

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Answer 1 · 2016-12-03T16:14:16

$-5/2e^(-2x)+e^-x+C$

rearrange as folows.

$int((5-e^x)/e^(2x))dx$

$=int(5/e^(2x)-e^x/e^(2x))dx$

$int(5e^(-2x)-e^(-x))dx$

$=-5/2e^(-2x)+e^-x+C$

How do you integrate int (5-e^x)/(e^(2x))dxint (5-e^x)/(e^(2x))dx?