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How do you integrate $\int \frac{2 x + 1}{(x + 8) (x - 1) (x - 3)}$ $int (2x+1)/((x+8)(x-1)(x-3))$ using partial fractions?

1 Answer

Frederico Guizini S.

Nov 12, 2016

See answer below:
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Explanation:

Continuation:

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