How do you integrate #int (2t^2-1)^2dt#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer bp Nov 21, 2016 #(4t^5)/5 -(4t^3)/3 +t +C# Explanation: Expand #(2t^2-1)^2 = 4t^4 - 4t^2 +1# Now integrate term by term, #int (4t^4-4t^2+1)dt = (4t^5)/5 -(4t^3)/3 +t +C# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 10595 views around the world You can reuse this answer Creative Commons License