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How do you integrate #int (2t^2-1)^2dt#?

1 Answer

Nov 21, 2016

#(4t^5)/5 -(4t^3)/3 +t +C#

Explanation:

Expand #(2t^2-1)^2 = 4t^4 - 4t^2 +1#

Now integrate term by term,

#int (4t^4-4t^2+1)dt = (4t^5)/5 -(4t^3)/3 +t +C#

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