How do you integrate int 2^xdx from [-1,2]? Calculus Introduction to Integration Integrals of Exponential Functions 1 Answer Narad T. Dec 15, 2016 The answer is =7/(2ln2)=5.05 Explanation: Let u=2^x lnu=xln2 u=e^(xln2) int2^xdx=inte^(xln2)dx=e^(xln2)/ln2=2^x/ln2 int_-1^2 2^xdx= [2^x/ln2] _-1^2 =1/ln2(2^2-1/2) =1/ln2*7/2=5.05 Answer link Related questions How do you evaluate the integral inte^(4x) dx? How do you evaluate the integral inte^(-x) dx? How do you evaluate the integral int3^(x) dx? How do you evaluate the integral int3e^(x)-5e^(2x) dx? How do you evaluate the integral int10^(-x) dx? What is the integral of e^(x^3)? What is the integral of e^(0.5x)? What is the integral of e^(2x)? What is the integral of e^(7x)? What is the integral of 2e^(2x)? See all questions in Integrals of Exponential Functions Impact of this question 1419 views around the world You can reuse this answer Creative Commons License