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How do you integrate #e^sqrt(z) /sqrt(z) dz#?

1 Answer

A. S. Adikesavan

Sep 21, 2016

#2 e^sqrt z +C#

Explanation:

Use #(sqrt z)'=1/2(1/sqrtz)#

Here,

#int e^sqrt z/sqrt z dz#

#=2 int e^sqrt z (sqrt z)' dz#

#=2 int e^sqrt z d(sqrt z)#

#=2 e^sqrt z+C#

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