How do you integrate $(e^(2x-1))-1$ ?

Question

4298 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-20T14:45:00

$= 1/2e^(2x-1)- x + C$

$int \ (e^(2x-1))-1 \ dx$

$= int \ d/dx(1/2e^(2x-1))-1 \ dx$

$= 1/2e^(2x-1)- x + C$

How do you integrate (e^(2x-1))-1 (e^(2x-1))-1?