How do you identify the value of the discriminant for the equation $6x^2 = 2x – 1$ ?

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Answer 1 · 2018-03-20T01:16:45

$-20$ using Discriminant Formula: $b^2-4ac$

Let's get our quadratic equal to zero first. We can do this from subtracting $6x^2$ from both sides. We get:

$-6x^2+2x-1=0$

Our quadratic is in the form $ax^2+bx+c$ , where

$a=-6$
$b=2$
$c=-1$

The discriminant of a quadratic is $b^2-4ac$ , so we can just plug in these values. We get:

$(2)^2-4(-6)(-1)$

$=>4-4(6)$

$=>4-24=-20$

Therefore, our discriminant is $-20$ .

How do you identify the value of the discriminant for the equation 6x^2 = 2x – 16x^2 = 2x – 1?