How do you graph $y = {(x - 4)}^{2}$ $y=(x-4)^2$ by plotting points?

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Answer 1 · 2017-08-08T02:56:45

Refer to the explanation for the process.

Graph:

$y = {(x - 4)}^{2}$ $y=(x-4)^2$

This is a quadratic equation in vertex form: $y = a {(x - h)}^{2} + k$ $y=a(x-h)^2+k$ , where $k = 0$ $k=0$ , and the graph will be a parabola.

Choose values for $x$ $x$ and solve for $y$ $y$ . These will be your points.

$x = 0,$ $x=0,$ $y = 16$ $y=16$

$x = 1,$ $x=1,$ $y = 9$ $y=9$

$x = 2,$ $x=2,$ $y = 4$ $y=4$

$x = 3,$ $x=3,$ $y = 1$ $y=1$

$x = 4,$ $x=4,$ $y = 0$ $y=0$

$x = 5,$ $x=5,$ $y = 1$ $y=1$

$x = 6,$ $x=6,$ $y = 4$ $y=4$

$x = 7,$ $x=7,$ $y = 9$ $y=9$

$x = 8,$ $x=8,$ $y = 16$ $y=16$

There are 9 points. Plot them on a grid and sketch a parabola through the points.

graph{y=(x-4)^2 [-14.71, 17.32, -3.1, 12.92]}

How do you graph y=(x-4)^2 y=(x−4)2y=(x-4)^2 by plotting points?