How do you graph $y = {(x + 3)}^{2} + 5$ $y=(x+3)^2+5$ ?

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Answer 1 · 2017-07-05T09:00:38

By assigning values for x, compute y

If x is 0, your function $y = 14$ $y= 14$

If x is 1, your function $y = 21$ $y=21$

If x is 2, your function $y = 30$ $y=30$ etc. You can plot graph{5+(x+3)^2 [-40.34, 39.66, -2.88, 37.12]}

How do you graph y=(x+3)2+5y=(x+3)^2+5?