How do you graph #y= -x^2+4#?

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How do you graph #y= -x^2+4#?

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Answer 1 · 2015-06-02T06:19:46

Start by finding some values for #f(x)#

#f(-3)=-(-3)²+4=-9+4=-5#
#f(-2)=-(-2)²+4=-4+4=0#
#f(-1)=-(-1)²+4=-1+4=3#
#f(0)=-0²+4=0+4=4#
#f(1)=-1²+4=-1+4=3#
#f(2)=-2²+4=-4+4=0#
#f(3)=-3²+4=-9+4=-5#
graph{-(x^2)+4 [-5, 5, -5, 6]}

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How do you graph #y= -x^2+4#?

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