How do you graph $y = x^{2} - 3 x - 3$ $y=x^2-3x-3$ ?

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Answer 1 · 2017-07-25T12:11:05

By assigning different values for x, get y

If x is zero, you will get $y = - 3$ $y=-3$
If x is 1, you will get $y = - 5$ $y= -5$
If x is 2, you will get $y = - 5$ $y= -5$

etc. You can graph now:

graph{(x^2) - 3x - 3 [-7.48, 12.92, -5.82, 4.48]}

How do you graph y=x2−3x−3y=x^2-3x-3?