How do you graph #y= -x^2+2x+3#?

1 Answer
bp
Jun 19, 2016

Explained below

Explanation:

The given function is a quadratic function , which would represent a parabola. Hence it would be prudent to put it in the vertex form.

It would be y=#-(x^2 -2x) +3#

That is y = #-(x-1)^2 +4#

This shows that vertex is (1,4) and axis of symmetry is x=1. The parabola would open downwards because the coefficient of #x^2# is negative. y -intercept would be 3 and x intercepts would be -1 and 3. With all this information available, the parabola can be easily graphed.[For x intercepts put y=0 and factorise #-x^2 +2x-3=0]

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