How do you graph #y = (x - 2)^2 + 1#?

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Answer 1 · 2018-08-10T05:36:05

Refer Explanation

Given -

#y=(x-2)^2+1#

The equation is in the form #y=(x-h)+k#, then the vertex #(h,k)#.

In the given equation the vertex is #(2,1)#

Its y-intercept.

At #x=0; y=(0-2)^2+1=4+1=5#

y-intercept #(0,5)#

Its y - intercept #(0,5)#is above the vertex#(2,1)# the curve opens up. Hence it has no x-intercept.

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