How do you graph #y=x^2 + 1#?

1 Answer
Tony B
Feb 29, 2016

You asked "how" do you graph: I have given a full explanation as to the method.

Explanation:

#color(blue)("Some observations")#

The #x^2# is positive so the general graph shape is #uu#

Consider the generalised form of #y=ax^2+bx+c#

The #bx# part of the equation shifts the graph left or right. You do not have any #bx# type of value in your equation. So the graph is central about the y-axis.

The #c# part of the equation is of value +1 so it lifts the vertex up from y=0 to y=1
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("How to graph this equation")#

#color(blue)("Step 1")#

#color(brown)("Draw up a table of values that can be used to construct the graph")#

Tony B

#color(blue)("Step 2")#
Draw your y-axis as a vertical line and your x-axis as a horizontal line.

Mark the relevant points for the x and y values. Draw freehand as best as you can a smooth curve that passes through those points

Tony B

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