How do you graph $y = \sqrt{x - 2} + 3$ $y=sqrt(x-2)+3$ ?

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How do you graph $y = \sqrt{x - 2} + 3$ $y=sqrt(x-2)+3$ ?

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Answer 1 · 2016-07-28T11:59:05

See the explanation

Explanation:

Suppose there was an unknown value z

Then ${(- z)}^{2} = z^{2} and {(+ z)}^{2} = z^{2}$ $(-z)^2 =z^2" and "(+z)^2=z^2$

So $\sqrt{z^{2}} = \pm z$ $sqrt(z^2)=+-z$
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So in reality we have $y = \pm \sqrt{x - 2} + 3$ $y=+-sqrt(x-2)+3$

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Lets consider the relationship a different way. The above is such that $x$ $x$ is the independent variable and y the dependant variable. Suppose we reversed this.

Write as $\sqrt{x - 2} = y - 3$ $sqrt(x-2)=y-3$

Squaring both sides

$x - 2 = y^{2} - 6 y + 9$ $x-2=y^2-6y+9$

$x = y^{2} - 6 y + 11$ $x=y^2-6y+11$

If you plotted this then you would have the same graph as
$y = \pm \sqrt{x - 2} + 3$ $y=+-sqrt(x-2)+3$

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How do you graph $y = \sqrt{x - 2} + 3$ $y=sqrt(x-2)+3$ ?

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How do you graph y=√x−2+3y=sqrt(x-2)+3?

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How do you graph $y = \sqrt{x - 2} + 3$ $y=sqrt(x-2)+3$ ?