For the equation:
y=sqrt(x+2)
we can graph this starting with an understanding of the graph, sqrtx and adjusting from there. Let's take a look at that graph first:
graph{sqrtx [-1, 10, -3, 5]}
The graph of sqrtx starts at x=0, y=0 (since we're graphing in real numbers on the x and y axis, the value under the square root sign can't be negative) then passes through x=1, y=1 and x=4, y=2 and will head off to infinity.
So how do we now graph sqrt(x+2)? What will make the value under the square root sign equal 0? x=-2. And so the we'll have the same shape of graph, but moved 2 places to the left. It'll look like this:
graph{sqrt(x+2) [-3, 10, -3, 5]}