How do you graph y = sqrt (3x) + 4 by plotting point?

1 Answer
sankarankalyanam
Oct 7, 2017

y=sqrt(3x)+4
graph{sqrt(3x)+4 [-10.38, 9.62, -5, 5]}

y=sqrt3x+4
graph{sqrt3x+4 [-10.38, 9.62, -5, 5]}

Explanation:

1) If given equation is y=sqrt(3x)+4
x=0,y=4
x=1,y=sqrt3+4
x=2,y=sqrt6+4
x=3,y=7
Four points are (0,4),(1,5.732),(2,6.449),(3,7)

2) If given equation is y=sqrt3*x+4
Giving values for x, find corresponding value of y from the above equation and plot in a graph.
x=0,y=4
x=1,y=sqrt3+4
x=2,y=2sqrt3+4
x=-1,y=-sqrt3+4
Four points are (0,4),(1,5.732),(2,7.464),(-1,2.268)

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