How do you graph $y = log (x - 4)$ $y=log (x-4)$ ?

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How do you graph $y = log (x - 4)$ $y=log (x-4)$ ?

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Answer 1 · 2016-02-04T11:59:13

Graph shows the vertical asymptote at x nearing 4.

Explanation:

X must be more than 4 otherwise log(x-4) will be invalid;
Let us make a table of x & y
$x \to \to log (x - 4)$ $x rarr rarr log(x-4)$
------- ----------------
$5 \to \to 0$ $5 rarr rarr 0$
$9 \to \to .7$ $9 rarr rarr .7$
$14 \to \to 1$ $14 rarr rarr 1$
$19 \to \to 1.18$ $19 rarr rarr 1.18$
$24 \to \to 1.30$ $24 rarr rarr 1.30$
Now we can plot the Graph with the value of x and y.On this Graph Vertical asymptote is at x nearing the value 4.
graph{log(x-4) [-20, 20, -10, 10]}

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How do you graph $y = log (x - 4)$ $y=log (x-4)$ ?

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How do you graph y=log(x−4)y=log (x-4)?

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How do you graph $y = log (x - 4)$ $y=log (x-4)$ ?