How do you graph $y = arctan 4 x$ $y = arctan 4x$ ?

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Answer 1 · 2018-08-13T12:41:35

See $\infty - a r m$ $oo-arm$ single wave.

arctan values $\in (- \frac{π}{2}, \frac{π}{2})$ $in ( - pi/2, pi/2 )$

$y = arctan (4 x) \neq$ $y = arctan ( 4 x ) ne$ ( zeros of cos y ) $\pm \frac{π}{2}$ $+-pi/2$ .

Asymptotes: $y = \pm \frac{π}{2}$ $y = +- pi/2$

Period for x:: $\frac{π}{4}$ $pi/4$

See graph, depicting all these aspects.

graph{(y-arctan(4x))(y-pi/2)(y+pi/2)=0}.

Wholesome $\infty$ $oo$ -arm waves $↑ ↓$ $uarr darr$ , using the inverse

$x = \frac{1}{4} tan y$ $x = 1/4 tan y$ .

graph{4x-tan y = 0[-20 20 -10 10] }.

How do you graph y=arctan4xy = arctan 4x?