How do you graph $y = 7 \sqrt{x}$ $y=7sqrtx$ , compare it to the parent graph and what is the domain and range?

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Answer 1 · 2018-05-19T19:10:49

see graph.

Domain of both functions is $[0, \infty)$ $[0,oo)$

Range of both functions is $[0, \infty)$ $[0,oo)$

$y = a \sqrt{b x - c} + d$ $y=asqrt(bx -c) + d$

a = vertical stretch

so your equation: $y = 7 \sqrt{x}$ $y=7sqrtx$

a = 7
b = 1
c = 0
d = 0

so your graph will be the parent $f (x) = \sqrt{x}$ $f(x) = sqrtx$ stretched vertically by a factor of 7

Domain of both functions is $[0, \infty)$ $[0,oo)$

Range of both functions is $[0, \infty)$ $[0,oo)$

here is the parent graph:

graph{sqrtx [-10, 10, -5, 5]}

And here is yours:

graph{7sqrtx [-9.96, 10.04, -0.52, 9.48]}

How do you graph y=7√xy=7sqrtx, compare it to the parent graph and what is the domain and range?