How do you graph #y=5x-5# by plotting points?

1 Answer
May 7, 2018

Below

Explanation:

For x-intercepts, let #y=0#

#0=5x-5#
#5=5x#
#x=1# SO #(1,0)#

For y-intercepts, let #x=0#

#y=5(0)-5#
#y=-5# SO #(0,-5)#

Plot those two points on your graph and join them together.

graph{5-5x [-10, 10, -5, 5]}

An alternate way to graph this is basically go let #x=1# and sub it into the equation to get your y value. Then go let #x=2# and sub it into the equation and so on

Personally, I prefer the whole "finding the x and y intercepts"