How do you graph #y=5/2x-2# using intercepts?

1 Answer
David G.
May 20, 2017

We can find that the x-intercept is #(4/5, 0)# and the y-intercept is #(0, -2)#.

Drawing a straight line through these two points creates a graph of the function.

Explanation:

The x-intercept is the point at which the function meets the x-axis, which is the line #y=0#.

If we substitute #y=0# into the equation, we get:

#0=5/2x−2#

Rearranging,

#5/2x =2#

#5x = 4#

#x=4/5#

So one point on the line is the point #(4/5, 0)#.

The y-intercept, similarly, is the point at which the function meets the y-axis, which is the line #x=0#. Substituting #x=0# into the equation yields:

#y =5/2(0)-2#

#y=-2#

So the y-intercept is the point #(0, -2)#.

Simply drawing a line through these two points will create a graph of the function, using intercepts.

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