How do you graph $y=4x+8$ ?

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Answer 1 · 2017-04-08T16:00:04

Make a point at $(0,8)$ then move up 4 on the y and over 1 on the $x$ and make another point at $( 1,12)$ draw a line to connect the points.

The equation is in the $y = mx +b$ y intercept form. where

$m =$ the slope ( think mountain slope ski resort)
$b =$ the $y$ intercept ( think beginning pony)

The equation $y= 4x + 8$

$m = 4/1color(white)(000)$ The change in $y$ is 4 and the change in $x$ is 1
$b= 8color(white)(000)$ The line crosses the $y$ axis at $( 0,8)$

Start at the y intercept 8 make a point at $( 0,8)$ Then use the slope

Go up 4 on the $y$ axis

$8+ 4 = 12$ The $y$ value of the second point is 12

Go over 1 on the $x$ axis

$0 + 1 = 1$ the $x$ value of the second point is 1.

make a second point at $( 1,12)$ Connect the dots.

graph{4x+8 [-18.27, 13.77, -3.68, 12.35]}

How do you graph y=4x+8 y=4x+8?