How do you graph #y= 4x-2# by plotting points?

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Answer 1 · 2018-06-26T16:26:40

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (4 * 0) - 2#

#y = 0 - 2#

#y = -2# or #(0, -2)#

Second Point: For #x = 1#

#y = (4 * 1) - 2#

#y = 4 - 2#

#y = 2# or #(1, 2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 4x + 2)(x^2+(y+2)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}