How do you graph $y=4/3x+2$ ?

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Answer 1 · 2016-02-13T21:51:42

graph{y = 4/3 x + 2 [-10, 10, -4.96, 5.04]}

y = mx + b, slop intercept form

m=slope
=rise/run
=4/3

b=y-intercpt
=2
(0,2)

How do you graph y=4/3x+2y=4/3x+2?