How do you graph y=4/3sqrt(x)y=43x?

2 Answers
Apr 28, 2017

Try different x values and plot accordingly

Explanation:

If you assign x=1x=1 you will get your function y=4/3y=43

If you assign x=2x=2 you will get y=1.886y=1.886

If you assign x=3x=3 you will get y=2.309y=2.309

etc. On the negative side your function is not defined.

Now plot accordingly.

graph{(4/3)sqrtx [-3, 20, -2, 10]}

Apr 28, 2017

See explanation

Explanation:

Suppose the square root of xx is aa. Then the value of a may be positive or negative.

Example

(-2)^2=(+2)^2=4(2)2=(+2)2=4

So sqrt(4)=+-24=±2

Thus y=3/4 sqrt(x)" "y=34x is really y=+-3/4sqrt(x)y=±34x

If you wish the numbers to remain in the real domain ->RR then

y=+-3/4sqrt(-x) is not permitted

That is: x is a squared value but the squared value must not itself be negative.
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Consequently the graph is split into 2 parts

First part: " "y=+3/4sqrt(x)
Second part y=-3/4sqrt(x)

Tony B