How do you graph #y=3^x#?

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Answer 1 · 2016-02-08T07:12:12

To plot the graph of #y=3^x#, there is a need to determine some important (x, y) coordinates and asymptotes.

from the equation #y=3^x#, set #x=0#, then solve for #y# to determine the y-intercept.

#y=3^0=1# so one point on the graph is #(0, 1)#

Set x now to the very large value #+oo#, then solve for y.

#y=3^oo=oo# so conclusive to say that when #x# approaches #oo#
#y# approaches #oo# also

Set x now to the very negative value #-oo#, then solve for #y#.

#y=3^-oo=0#

therefore, at #x=-oo# the value of #y# approaches 0 and #y=0# is an asymptote.

the graph of #y=3^x#
graph{(y-3^x)=0[-10,10,5,5]}
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