How do you graph $y=3.00x+23$ ?

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Answer 1 · 2017-08-17T13:25:12

See a solution process below:

To graph a linear equation we need to plot two points on the line and then draw a line through them.

For $x = 0$

$y = (3.00 xx 0) + 23$

$y = 0 + 23$

$y = 23$ or $(0, 23)$

For $x = 1$

$y = (3.00 xx 1) + 23$

$y = 3.00 + 23$

$y = 26$ or $(1, 26)$

Next, we can plot the two points on the grid:

graph{(x^2+(y-23)^2-0.251)((x-1)^2+(y-26)^2-0.25)=0 [-35, 35, -5, 30]}

Now, we can draw the line through the two points:

graph{(x^2+(y-23)^2-0.251)((x-1)^2+(y-26)^2-0.25)(y-3x-23)=0 [-35, 35, -5, 30]}

How do you graph y=3.00x+23y=3.00x+23?