How do you graph $y = - 2 x - 3$ $y=-2x-3$ ?

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Answer 1 · 2018-03-20T23:13:47

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (- 2 \cdot 0) - 3$ $y = (-2 * 0) - 3$

$y = 0 - 3$ $y = 0 - 3$

$y = - 3$ $y = -3$ or $(0, - 3)$ $(0, -3)$

Second Point: For $x = - 1$ $x = -1$

$y = (- 2 \cdot - 1) - 3$ $y = (-2 * -1) - 3$

$y = 2 - 3$ $y = 2 - 3$

$y = - 1$ $y = -1$ or $(- 1, - 1)$ $(-1, -1)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.035)((x+1)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + 2x + 3)(x^2+(y+3)^2-0.035)((x+1)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

How do you graph y=-2x-3y=−2x−3y=-2x-3?