How do you graph #y=2sin(x - pi)#?

1 Answer
Alan P.
Aug 28, 2015

Sketch #y=sin(x)# then redraw replacing each #y# coordinate with #(-2)xxy#

Explanation:

#sin(x-pi) = -sin(x)#
#rArr 2sin(x-pi) = -2sin(x)#

The graph of #y_1=-2sin(x)# is identical to the graph of #y_2=sin(x)# except for any value of #x#, #y_1 = (-2)*y_1#

Graph of #sin(x)#
graph{sin(x) [-6.33, 13.67, -4.88, 5.12]}

Graph of #-2sin(x)#
graph{-2sin(x) [-6.33, 13.67, -4.88, 5.12]}

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