How do you graph $Y = 2^{x} + 3$ $Y=2^x+3$ by plotting points?

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Answer 1 · 2017-04-21T00:19:16

Aysmptote is already given. Sub in $x$ $x$ -values and solve for $y$ $y$ .

This graph is slightly easier to graph than the other exponential functions.

The base function is $2$ $2$ , describing the increase rate as the function's $x$ $x$ -value increases.

The only transformation that's done is a translation $3$ $3$ units up. This gives us the asymptote of $y > 3$ $y>3$ .

graph{(2^x) + 3 [-10, 10, -5, 5]}

Now, we need to plot the points. We can simply just sub $x$ $x$ as $- 1$ $-1$ , $0$ $0$ , and $1$ $1$ , and solve for $y$ $y$ .

Doing so gives us $\frac{7}{2} \to 3.5$ $7/2 ->3.5$ , $4$ $4$ , and $5$ $5$ respectively.

Connect the dots in a curving motion. Make sure when you extend the function in the 2nd quadrant, that it never touches $3$ $3$ .

Hope this helps :)

How do you graph Y=2^x+3Y=2x+3Y=2^x+3 by plotting points?