How do you graph #y = 2^x + 2#?

1 Answer
Tony B
Apr 21, 2016

See explanation

Explanation:

Produce a table of values comparing x to y something like this:
Tony B

Plot your points and draw a curve as best as you can through those points. Your graph should look something like that below. You do not need to label all the points. Good idea to label key points though.

At #x=0 -> y=1+2=3->y_("intercept")#

For #x < 0 -> y=1/(2^(|x|)) +2=> lim_(x->-oo)y-> "Asymptote of "y=2#

Tony B

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