How do you graph #y= -2/3x +4# by plotting points?

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Answer 1 · 2018-03-10T16:53:36

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (-2/3 * 0) + 4#

#y = 0 + 4#

#y = 4# or #(0, 4)#

Second Point: For #x = 3#

#y = (-2/3 * 3) + 4#

#y = -2 + 4#

#y = 2# or #(3, 2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.04)((x-3)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (2/3)x-4)(x^2+(y-4)^2-0.04)((x-3)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}