How do you graph $y = - \frac{2}{3} x$ $y=-2/3x$ ?

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Answer 1 · 2018-03-18T14:16:22

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = - \frac{2}{3} \times 0$ $y = -2/3 xx 0$

$y = 0$ $y = 0$ or $(0, 0)$ $(0, 0)$

Second Point: For $x = 3$ $x = 3$

$y = - \frac{2}{3} \times 3$ $y = -2/3 xx 3$

$y = - \frac{6}{3}$ $y = -6/3$

$y = - 2$ $y = -2$ or $(3, - 2)$ $(3, -2)$

We can next plot the two points on the coordinate plane:

graph{(x^2+y^2-0.035)((x-3)^2+(y+2)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (2/3)x)(x^2+y^2-0.035)((x-3)^2+(y+2)^2-0.035)=0 [-10, 10, -5, 5]}

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