How do you graph #y=-2/3x#?

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Answer 1 · 2018-03-18T14:16:22

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = -2/3 xx 0#

#y = 0# or #(0, 0)#

Second Point: For #x = 3#

#y = -2/3 xx 3#

#y = -6/3#

#y = -2# or #(3, -2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+y^2-0.035)((x-3)^2+(y+2)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (2/3)x)(x^2+y^2-0.035)((x-3)^2+(y+2)^2-0.035)=0 [-10, 10, -5, 5]}