How do you graph $y - 2 = 3 (x + 5)$ $y-2=3(x+5)$ ?

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How do you graph $y - 2 = 3 (x + 5)$ $y-2=3(x+5)$ ?

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Answer 1 · 2015-02-04T18:34:29

First of all, let's do some manipulations: expanding the product on the right side, we get
$y - 2 = 3 x + 15$ $y-2=3x+15$
Adding 2 at both sides:
$y = 3 x + 17$ $y=3x+17$
Now we have expressed the line in the standard form $y = a x + b$ $y=ax+b$ . To draw a line, you need to have two point which surely belong to the line, and then connect them. Let's choose two easy points: for $x = 0$ $x=0$ we have $y = 17$ $y=17$ , so the point $(0, 17)$ $(0,17)$ belongs to the line. If $x = - 5$ $x=-5$ , we have $y = - 15 + 17 = 2$ $y=-15+17=2$ , so the point $(- 5, 2)$ $(-5,2)$ also belongs to the line. Now, you just need to draw them on the plain and then connect them. Here's the graph:
graph{y=3x+17 [-23.1, 28.2, -9.25, 16.42]}

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How do you graph $y - 2 = 3 (x + 5)$ $y-2=3(x+5)$ ?

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