How do you graph # y = (-2/3)x + 4# by plotting points?

1 Answer
iceman
Jun 27, 2017

Now draw a line passing through the points:(0, 4) and (6, 0).

Explanation:

#y=(-2/3)x+4# => equation of a line in slope-intercept form
To draw a straight line all you need is two points on the line, then you can draw a line passing through the points.

Give some values to x then solve for y:
#x = 0#
#y=(-2/3)*0+4#
#y=4# => so point (0, 4) is on the line
#x = 6#
#y=(-2/3)*6+4#
#y=-4+4#
#y=0# => so point (6, 0) is on the line
Now draw a line passing through the points:(0, 4) and (6, 0).

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