How do you graph $y = 2^{2 x}$ $y=2^(2x)$ using a table of values?

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How do you graph $y = 2^{2 x}$ $y=2^(2x)$ using a table of values?

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Answer 1 · 2016-02-02T19:05:16

I tried few values:

Explanation:

I would use "friendly" values for $x$ $x$ to avoid difficult and complicated evaluations (basically, values that I can easily evaluate).
I'll try:
$x = - 1$ $x=-1$ so that $y = 2^{- 2} = \frac{1}{4} = 0.25$ $y=2^(-2)=1/4=0.25$
$x = - \frac{1}{2}$ $x=-1/2$ so that $y = 2^{- 2 \cdot \frac{1}{2}} = 2^{- 1} = \frac{1}{2} = 0.5$ $y=2^(-2*1/2)=2^-1=1/2=0.5$
$x = 0$ $x=0$ so that $y = 2^{0} = 1$ $y=2^0=1$
$x = \frac{1}{2}$ $x=1/2$ so that $y = 2^{2 \cdot \frac{1}{2}} = 2^{1} = 2$ $y=2^(2*1/2)=2^1=2$
$x = 1$ $x=1$ so that $y = 2^{2 \cdot 1} = 4$ $y=2^(2*1)=4$
$x = \frac{3}{2}$ $x=3/2$ so that $y = 2^{2 \cdot \frac{3}{2}} = 2^{3} = 8$ $y=2^(2*3/2)=2^3=8$

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How do you graph $y = 2^{2 x}$ $y=2^(2x)$ using a table of values?

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