How do you graph $y=1+sqrt(x-3)$ ?

Question

3152 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-16T08:58:25

Graph is inserted. See the vertex (3, 1) at the $larr$ end

graph{1+sqrt(x-3)2 [0, 10, -10, 10]}

The equation $(y-1)^2=x-1$ representing the parabola of size a = 1/4

and with vertex V(3, 1) is the combined equation to the pair

$y-1=+-sqrt(x-3)$

representing two halves of the parabola.

Here,

As $sqrt(x-3)>=0, x >=3 and y >=1$ .

The graph for the other half given by $y = 1-sqrt(x-3)$ follows.

graph{1-sqrt(x-3) [0, 10, -10, 10]}

How do you graph y=1+sqrt(x-3)y=1+sqrt(x-3)?