How do you graph y=15x−3 by plotting points?

1 Answer
Sridhar V.
May 12, 2018


Graphs are available for:
f(x)=x,f(x)=(15)⋅xandf(x)=[(15)⋅x]−3
for easy comprehension.

Explanation:


Step 1:

Examine the graph of y=f(x)=x

enter image source here

Slope-Intercept Form y=mx+b

This is of the form y=1⋅x+0, where Slope(m)=1 and y-intercept=0

Remember that the Slope(m) is the constant ratio that compares the change in y values over the change in x values between any two points.

y-intercept ** is the coordinate point where the graph crosses the y-axis**.

Step 2:

Examine the graph of y=f(x)=(15)⋅x

enter image source here

This graph is also in Slope-Intercept Form : y=mx+b, where Slope(m)=(15) and **y-intercept ** is 0.

Step 3:

First we will create a data table for x and the corresponding y values:

enter image source here

Construct the graph using these data values.

Examine the graph of y=f(x)=(15)⋅x−3

enter image source here

The equation is of y=mx+b form:

Slope(m)=15 and y-intercept =(0,−3)

Hope you find this solution useful.

Related questions
See all questions in Graphs in the Coordinate Plane
Impact of this question
13972 views around the world
You can reuse this answer
Creative Commons License