How do you graph #y=1/5x-3# by plotting points?

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Answer 1 · 2018-05-12T08:01:26

#" "#
Graphs are available for:
#color(blue)(f(x) = x, color(green)(f(x) = (1/5)*x and color(brown)(f(x)=[(1/5)*x]-3#
for easy comprehension.

#" "#
#color(green)("Step 1:"#

Examine the graph of #color(blue)(y=f(x)=x#

enter image source here

Slope-Intercept Form #y= mx+b#

This is of the form #y=1*x+0#, where #Slope(m)=1# and #"y-intercept"=0#

Remember that the Slope(m) is the constant ratio that compares the change in y values over the change in x values between any two points.

y-intercept is the coordinate point where the graph crosses the y-axis.

#color(green)("Step 2:"#

Examine the graph of #color(green)(y=f(x)=(1/5)*x#

enter image source here

This graph is also in Slope-Intercept Form : #y=mx+b#, where #Slope(m)=(1/5)# and y-intercept is #0#.

#color(green)("Step 3:"#

First we will create a data table for #x# and the corresponding #y# values:

enter image source here

Construct the graph using these data values.

Examine the graph of #color(brown)(y=f(x)=(1/5)*x-3#

enter image source here

The equation is of #y=mx+b# form:

#Slope(m)=1/5# and y-intercept #=(0,-3)#

Hope you find this solution useful.