How do you graph y=14x−3 by plotting points?

1 Answer
Alan N.
May 13, 2018

See below.

Explanation:

y=14x−3

We know that the equation of a straight line with slope (m) and y−intercept (c) is: y=mx+c

Hence, in this example we have a linear function (y) with slope 14 and y− intercept −3

To graph a straight line by plotting points only requires two distinct points.

Since the y−intercept is −3 we already know that the point (0,−3) is on the line.

Now let's find the x−intercept, where y=0

0=14x−3

14x=3

x=12→(12,0) is on the line.

Now we can plot the two points: (0,−3)and(12,0) and draw a straight line between them and extending indefinitely in both directions, as shown below.

graph{(y-(x/4-3))(x^2+(y+3)^2-0.1)((x-12)^2+y^2-0.1)=0 [-11.35, 20.67, -7.3, 8.72]}

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