How do you graph $y = \frac{1}{4} x + 2$ $y=1/4x+2$ ?

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How do you graph $y = \frac{1}{4} x + 2$ $y=1/4x+2$ ?

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Answer 1 · 2016-07-14T00:00:24

Quickest way is to find the $x$ $x$ and $y$ $y$ intercepts

Explanation:

$x -$ $x-$ intercept is when $y = 0$ $y=0$
$0 = \frac{1}{4} x + 2 \to \frac{1}{4} x = - 2 \to x = - 8$ $0=1/4 x+2->1/4 x=-2->x=-8$
So the $x -$ $x-$ intercept is at $(- 8, 0)$ $(-8,0)$

$y -$ $y-$ intercept is when $x = 0$ $x=0$
$y = \frac{1}{4} \cdot 0 + 2 = 2$ $y=1/4 *0+2=2$
So the $y -$ $y-$ intercept is at $(0, 2)$ $(0,2)$

Now draw a line through these points, because it is a linear equation.
graph{x/4+2 [-11.58, 10.92, -2.295, 8.955]}

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How do you graph $y = \frac{1}{4} x + 2$ $y=1/4x+2$ ?

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