How do you graph $y=1/3x-4$ using intercepts?

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How do you graph $y=1/3x-4$ using intercepts?

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Answer 1 · 2017-04-18T06:31:03

The $y$ intercept is when $x=0$

$y=1/3x-4$ $=>$ $y=1/3(0)-4$ $=>$ $y=-4$

When $x=0$ , $y$ is $-4$ , so you have the point $(0,-4)$

The $x$ intercept is when $y=0$

$y=1/3x-4$ $=>$ $0=1/3x-4$

$1/3x=4$ $=>$ $cancel(3*1/3)x=4*3$

$x=12$

When $y=0$ , $x$ is $12$ , so you have the point $(12, 0)$

You have these two points, plot them in the graph and connect them by a straight line extended beyond them. By this you have done the graphing by using intercepts.

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How do you graph $y=1/3x-4$ using intercepts?

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How do you graph y=1/3x-4y=1/3x-4 using intercepts?

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How do you graph $y=1/3x-4$ using intercepts?