How do you graph #y=1/2sqrtx#?

1 Answer
Sridhar V.
Jul 22, 2018

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Please read the explanation.

Explanation:

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Create adata table to generate the graph:

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Observe the graphs given below:

  1. Graph of #color(blue)(y=sqrt(x)#

  2. Graph of #color(red)(y=(1/2)*sqrt(x)#

The radical function: #color(blue)(y=sqrt(x)# is the Parent Function:

The graph of the parent function starts at the origin #(0,0)#

The graph increases gradually.

The general form of the radical function:

#color(red)(y= f(x)=a sqrt[b(x-c)] +d#, where

( i). #color(red)(|a|# will stretch or shrink the graph vertically

( ii), #color(red)(|b|# will stretch or shrink the graph horizontally

(iii). #color(red)(c# will shift the graph left or right.

( iv). #color(red)(d# will shift the graph up or down.

( v). #color(red)(-a# will flip the graph across -axis

( vi). #color(red)(-b# will flip the graph across y-axis

We can compare both the graphs (parent function and the function given) to comprehend the behavior of the graph and the corresponding radical function.

enter image source here

Hope it helps.

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