How do you graph #y= -1/2+3# by plotting points?

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Answer 1 · 2018-06-18T13:01:41

Assumption: You mean the question as written.

Given: #y=-1/2+3#

#=>y=2 1/2 = 2.5#

What we have is #y="some constant value"#

This situation results in a straight line that is parallel to the x-axis and passes through the point #(x,y) =(x,2 1/2)#

In other words: you can use any value you wish for #x# but #y# is always #2 1/2#

Plotting points:
Tony B

Tony B

Answer 2 · 2018-06-18T13:19:22

Assumption: You mean the question to be #y=-1/2+3x#

One of the standardised forms is #y=mx+c#

Where #m# is the gradient (slope) and #c# is the y-intercept.

Thus we have:

#y=mx+c color(white)("d") -> color(white)("d") y=3x-1/2#

Tony B