How do you graph y = 1/(1 + x^2)?

1 Answer
Mar 14, 2016

See explanantion

Explanation:

As you have x^2 then 1+x^2 will always be positive. So y is always positive.

As x becomes smaller and smaller then 1/(1+x^2) -> 1/1 = 1

So lim_(x->0) 1/(1+x^2)=1

As x becomes bigger and bigger then 1+x^2 becomes bigger so 1/(1+x^2) becomes smaller.

lim_(x->+-oo) 1/(1+x^2)=0

color(blue)("build a table of value for different values of "x" and calculate the appropriate values of y. Plot")color(blue)(" the obtained values of y against those chosen for x")

Tony B