As you have x^2 then 1+x^2 will always be positive. So y is always positive.
As x becomes smaller and smaller then 1/(1+x^2) -> 1/1 = 1
So lim_(x->0) 1/(1+x^2)=1
As x becomes bigger and bigger then 1+x^2 becomes bigger so 1/(1+x^2) becomes smaller.
lim_(x->+-oo) 1/(1+x^2)=0
color(blue)("build a table of value for different values of "x" and calculate the appropriate values of y. Plot")color(blue)(" the obtained values of y against those chosen for x")