How do you graph x+y=3 by plotting points?
2 Answers
Aug 2, 2018
Please read the explanation.
Explanation:
Given:
Rewrite this equation as
We can create a data table for this linear equation and graph:
Plot some of the points from the table on the graph:
Hope it helps.
Aug 2, 2018
Explanation:
"one way is to find the intercepts, that is where the graph"
"crosses the x and y axes"
• " let x = 0, in the equation for y-intercept"
• " let y = 0, in the equation for x-intercept"
x=0rArry=3larrcolor(red)"y-intercept"
y=0rArrx=3larrcolor(red)"x-intercept"
"Plot the points "(0,3)" and "(3,0)
"Draw a straight line through them for graph"
graph{(y+x-3)((x-0)^2+(y-3)^2-0.04)((x-3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}
