How do you graph #x+y=1# using a table of values?

1 Answer
Meave60
Nov 4, 2015

Refer to the Explanation.

Explanation:

#x+y=1#

First solve for #y#. This will put the equation into slope-intercept form.

#y=-x+1#

Table of Values
#x=2,# #y=-1#
#x=1,# #y=0#
#x=0,# #y=1#

Plot the points and draw a straight line through the points.

graph{y=-x+1 [-9.14, 10.86, -3.03, 6.97]}

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