How do you graph #x + 4y = -4# by plotting points?

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Answer 1 · 2017-08-21T21:10:35

See a solution process below:

For a linear equation we can plot two points and then draw a line through the points to graph the line.

For #x = 0#

#0 + 4y = -4#

#4y = -4#

#(4y)/color(red)(4) = -4/color(red)(4)#

#y = -1# or #(0, -1)#

For #y = 0#

#x + (4 * 0) = -4#

#x + 0 = -4#

#x = -4# or #(-4, 0)#

We can now plot the two points on the graph:

graph{(x^2+(y+1)^2-0.025)((x+4)^2+y^2-0.025)=0}

Now we can draw a line through the points to graph the line:

graph{(x+4y+4)(x^2+(y+1)^2-0.025)((x+4)^2+y^2-0.025)=0}