How do you graph x-4y=12 using intercepts?

2 Answers
Harish Chandra Rajpoot
Jun 28, 2018

Given straight line: x-4y=12 can be re-written in intercept form as follows

x/12-{4y}/12=1

x/12+y/{-3}=1

The above straight line has x-intercept 12 & y-intercept -3

Take the x-intercept 12 units on x-axis & y-intercept 3 units on -ve y-axis & join both the end-points by a straight line to get the graph/plot

Jim G.
Jun 28, 2018

"see explanation"

Explanation:

"to find the intercepts, that is where the graph crosses"
"the x and y axes"

• " let x = 0, in the equation for y-intercept"

"let y = 0, in the equation for x-intercept"

x=0rArr-4y=12rArry=-3larrcolor(red)"y-intercept"

y=0rArrx=12larrcolor(red)"x-intercept"

"plot the points "(0,-3)" and "(12,0)

"Draw a straight line through them for graph"
graph{(y-1/4x+3)((x-0)^2+(y+3)^2-0.04)((x-12)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}

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