How do you graph x^2 + y^2 + 8x - 6y + 16 = 0x2+y2+8x6y+16=0?

1 Answer
Apr 11, 2016

x^2+y^2+8x-6y+16=0x2+y2+8x6y+16=0
is a circle with radius 33 and center (-4,3)(4,3)

Explanation:

x^2+y^2+8x-6y+16=0x2+y2+8x6y+16=0

rArr (x^2+8x+16)+(y^x-6ycolor(red)(+9)=0color(red)(+9)(x2+8x+16)+(yx6y+9=0+9

rArr (x+4)^2+(y-3)^2=3^^2(x+4)2+(y3)2=32
color(white)("XXX")XXXwhich is the general form for a circle with center (-4,3)(4,3) and radius 33
graph{x^2+y^2+8x-6y+16=0 [-9.636, 4.41, -0.826, 6.196]}